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Class 12 Physics Case Study Questions of Chapter 1 Electric Charges and Fields

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In Class 12 Boards there will be Case studies and Passage Based Questions will be asked, So practice these types of questions. Study Rate is always there to help you. Free PDF Download of CBSE Class 12 Physics Chapter 1 Electric Charges and Fields Case Study and Passage-Based Questions with Answers were Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 12 Physics Case Study Questions   Electric Charges and Fields  to know their preparation level.

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In CBSE Class 12 Physics Paper, Students will have to answer some questions based on  Assertion and Reason . There will be a few questions based on case studies and passage-based as well. In that, a paragraph will be given, and then the MCQ questions based on it will be asked.

Electric Charges and Fields Case Study Questions With Answers

Here, we have provided case-based/passage-based questions for Class 12 Physics  Chapter 1 Electric Charges and Fields

Case Study/Passage-Based Questions

case study questions for class 12 physics chapter 1

Answer: (a) 6.40 x 10-19 C

(ii) Extra electrons on this particular oil drop (given the presently known charge of the electron) are

Answer: (a) 4

(iii) A negatively charged oil drop is prevented from falling under gravity by applying a vertical electric field 100 V m -1 .If the mass of the drop is 1.6 X 10 -3  g, the number of electrons carried by the drop is (g= 10 m s -2 )

Answer: (c) 1012 .

(iv) The important conclusion given by Millikan’s experiment about the charge is

Answer: (c) charge is quantized

(v) If in Millikan’s oil drop experiment, charges on drops are found to be 8μC,12μC,20μC8μC,12μC,20μC then quanta of charge is

Answer:  (d) 4μC

Case Study 2: Surface Charge Density. Surface charge density is defined as the charge per unit surface area the surface (Arial) charge symmetric distribution and follow Gauss law of electrostatics mathematical term of surface charge density σ=ΔQ/ΔS

case study questions for class 12 physics chapter 1

Two large thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite sign (± s). Having magnitude 8.8 × 10 –12  cm –2  as shown here. The intensity of electrified at a point is E =σ/ε 0   and flux is Φ=E.ΔS, where ΔS = 1 m 2  (unit arial plate)

(i) E in the outer region (I) of the first (A) plate is (a) 1.7 × 10 –22  N/C (b) 1.1 × 10 –12  V/m (c) Zero (d) Insufficient data

Ans. (c) Zero C

(ii) E in the outer region (III) of the second plate (B) is (a) 1 N/C (b) 0.1 V/m (c) 0.5 N/C (d) zero

Ans. (d) Zero

(iii) E between (II) the plate is (a) 1 N/C (b) 0.1 V/m (c) 0.5 N/C (d) None of these

Ans. (d) None of these

(iv) The ratio of E from left side of plate A at distance 1 cm and 2 m respectively is (a) 1 : 2 (b) 10 : 2 (c) 1 : 1 (d) 20 : 1

Ans. (c) 1 : 1

(v) In order to estimate the electric field due to a thin finite plane metal plate the Gaussian surface considered is (a) Spherical (b) Linear (c) Cylindrical (d) Cybic

Ans. (c) Cylindrical

Case Study 3: Electric Charges and Fields, focuses on the basic properties of electric charges, the concept of electric fields, and the forces acting within these fields. The chapter introduces the idea that like charges repel, and unlike charges attract, a fundamental law of electrostatics. It also discusses the principle of superposition, which states that the net electrostatic force experienced by a charge due to multiple charges is simply the vector sum of the individual forces exerted by each charge independently. Further, the chapter introduces the concept of an electric field, defined as the electric force experienced by a unit positive charge at a point in space, and illustrates the way these fields are represented using field lines.

What is the basic property of electric charges?

A) Like charges repel, and unlike charges attract.

B) Like charges attract, and unlike charges repel.

C) All charges repel.

D) All charges attract.

Ans. A) Like charges repel, and unlike charges attract.

What does the principle of superposition state in terms of electrostatic forces?

A) The net electrostatic force is equal to the sum of the individual forces.

B) The net electrostatic force is equal to the difference of the individual forces.

C) The net electrostatic force is independent of the individual forces.

D) The net electrostatic force is inversely proportional to the individual forces.

Ans. A) The net electrostatic force is equal to the sum of the individual forces.

What is an electric field?

A) The region around a charge where magnetic force is experienced.

B) The region around a charge where gravitational force is experienced.

C) The region around a charge where electrostatic force is experienced.

D) The region around a charge where nuclear force is experienced.

Ans. C) The region around a charge where electrostatic force is experienced.

How is the electric field defined?

A) As the electric force experienced by a unit negative charge.

B) As the electric force experienced by a unit positive charge.

C) As the gravitational force experienced by a unit positive charge.

D) As the magnetic force experienced by a unit positive charge.

Ans. B) As the electric force experienced by a unit positive charge.

How are electric fields represented?

A) By field lines.

B) By electric charges.

C) By vectors.

D) By matrices.

Ans. A) By field lines.

Hope the information shed above regarding Case Study and Passage Based Questions for Class 12 Physics Chapter 1 Electric Charges and Fields with Answers Pdf free download has been useful to an extent. If you have any other queries about CBSE Class 12 Physics Electric Charges and Fields Case Study and Passage Based Questions with Answers, feel free to comment below so that we can revert back to us at the earliest possible. By Team Study Rate

case study questions for class 12 physics chapter 1

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Case Study on Electric Charges and Fields Class 12 Physics PDF

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  • Read the Case Carefully: To start gathering insights from the given case-based questions, it is vital to read the Electric Charges and Fields case carefully and identify the key facts, figures, and units of measurement. Pay attention to any diagrams or graphs related to Electric Charges and Fields provided, as they may contain important information.
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Case Study Questions Class 12 Physics Electric Charges and Fields

Case study questions class 12 physics chapter 1 electric charges and fields.

CBSE Class 12 Case Study Questions Physics Electric Charges and Fields. Here we have arranged some Important Case Base Questions for students who are searching for Paragraph Based Questions Electric Charges and Fields.

At Case Study Questions there will given a Paragraph. In where some Important Questions will made on that respective Case Based Study. There will various types of marks will given 1 marks, 2 marks, 3 marks, 4 marks.

electrical charges and fields case based questions

1.) Read the following paragraph and answer the following questions from 1.1 to  1.4 :

Charge is a property of matter that can be in two forms: positive charge and negative charge. If two objects which are having the same sign of charge repel to each other,  and on the other hand objects which have opposite sign charges attract to each other. Electric field concept comes from

The concept of an electric field arises from the effect of a charge body in the space around the body. When a charged particle is placed in a space and it feels some electric force we can say there is an electric field.

Electric field is a vector quantity that means it has magnitude and direction both.

Electric field at any point can be defined as a force on a unit charge particle.

This unit charge is called a test charge, and the direction of the electric field is defined as a force direction on a positive  test charge , and force on a charge particle in an electric field is given by F=qE.

1.1   Define electric field and how we can find direction of electric field ?

1.2   Choose the correct options from the following given below.

If two bodies have like charges and opposite charges how will they behave ?

A.) In both cases they will repel.

B.) In both cases they will attract.

C.) They will repel when both have the same charge and attract each other when both have opposite charges.

D.) They will attract when both have the same charge and repel each other when both have opposite charges.

1.3   If Force acting on a test charge of 5C , is 25 N along north direction then what will be electric field intensity at that point.

Electric field  or electric field intensity at any point can be defined as a force on a unit charge particle. And we know that force on a charge particle is given by F=qE

From them we can wright E = F/q

And the direction of the electric field will be  along  the force on the positive charge particle or on the negative charge particle opposite to the force direction.

(C)   They will repel when both have the same charge and attract each other when both have opposite charges.

When both bodies have the same charges they will repel each other and on the other hand they will attract each other when both bodies have different charges.

Given test charge value = 5C

And force on the test charge is 25N

We know that electric field intensity is defined as the force on per unit  test charge.

So E = F/q = 25/5 = 5 N/C

And Direction of the electric field intensity is along the force direction that is along the north.

2.) Read the following paragraph and answer the following questions from 2.1 to 2.3

E lectric field is a basic property of a charge particle. When a charge particle is placed in a space it will create an electric field around it in all possible directions and that will be inversely proportional to the square of the distance from the point charge.

As we know electric field is a vector quantity so due to more than one point charges electric field intensity can be calculated at any point as a vector sum of due to all point charges intensity and direction will be along the resultant vector direction.If at any point electric field is uniform can be drawn as a parallel line and if electric field is non- uniform it can be drawn non-parallel line but when then electric field line near to each other we can say there is a strong electric field compare to other point, where electric field line is little bit far away that means we can say electric field line density is directly proportional to electric field strength.And this electric field lines never intersect to each other. The electric field strength measure in V/m

2.1 How can electric field strength be measured ? And what is its SI unit ?

2.2 Why electric field lines never intersect with each other?

2.3 Let there be two point charges in space. Charge Q1= +3 μC is  at coordinates (0, 0), and charge Q2 = -1 μC is at coordinates (6m, 0). Calculate the resultant  electric field at a point P, which is at (3m, 0m), and  also calculate force by this electric field on a +2 μC test charge which is placed at the same point P(3m,0).

Electric field can be measure by two ways:

1.) By placing a test charge on that point we can measure the electric field strength, first we calculate the force on test charge and we divide test charge value to force by this method we can calculate the electric field.

2.) Or if we know the field pattern we can say where the electric field is high in magnitude and where is low but by this method we can not determine magnitude of electric electric field strength.

And It’s SI unit is defined is a Volt/meter

Electric field lines never intersect with each other , because if electric field vector quantity means it has both magnitude and direction as well , if electric field lines intersect to each other we can be drawn to tangents on intersecting points which show its two directions at the same point which is impossible. Means electric field lines never intersect to each other.

Physics class 12

3.) Read the following paragraph and answer the following questions from 3.1 to 3.3

When two charge or more charged particle placed at a distance then  they will create a magnetic field due to this electric field they will exert an electric force on each other, this force can be calculated by Coulomb’s law, which states that force between two charge particles is directly proportional to magnitude of the charge particle and inversely proportional to square distance between them.Coulomb’s force between two charged particle depends on medium between them , when a medium of dielectric constant K is placed between two charged particle electric force decrease by K times

case study questions for class 12 physics chapter 1

3.1 when two charges, q_1and q_2 are brought closer to each other without changing their magnitude, what will be the effect on electrostatic force between them?

A.) Decrease

B.) Increase

C.) Remain same

D.) Data is not sufficient

3.2 Two charge values of +2 μC and -4 μC are placed at 2m distance. Find the electrostatic force between these two charge particles?

3.3 Choose the correct statement from the given below.

Assertion(A): Electric force between two point charges depends upon the magnitudes of the two charges and  also depends upon the distance between them.

Reason(R): Coulomb’s law defines the electrostatic force (F) is directly proportional to the product of magnitude of their charges and inversely proportional to the square of the distance (r) between two charges.

A. Both Assertion and Reason are true, and Reason is the correct explanation of reason.

B. Both Assertion and Reason are true, but Reason is NOT the correct explanation of Assertion.

C. Assertion is true, but Reason is false.

D. Assertion is false, but Reason is true

when two charges, and  are brought closer to each other without changing their magnitude, electrostatic force between them will increase because force is inversely proportional to distance square.

By Coulomb’s law electrostatic force (F) between two point charges can be

case study questions for class 12 physics chapter 1

A. Both Assertion and Reason are true, and Reason is the correct explanation of reason. By Coulomb’s law we can explain it.

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