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3rd grade (Eureka Math/EngageNY)

Unit 1: module 1: properties of multiplication and division and solving problems with units of 2–5 and 10, unit 2: module 2: place value and problem solving with units of measure, unit 3: module 3: multiplication and division with units of 0, 1, 6–9, and multiples of 10, unit 4: module 4: multiplication and area, unit 5: module 5: fractions as numbers on the number line, unit 6: module 6: collecting and displaying data, unit 7: module 7: geometry and measurement word problems.

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Home > CCA > Chapter 3 > Lesson 3.3.1

Lesson 3.1.1, lesson 3.1.2, lesson 3.2.1, lesson 3.2.2, lesson 3.2.3, lesson 3.2.4, lesson 3.3.1, lesson 3.3.2, lesson 3.3.3.

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Eureka Math Grade 3 Module 4 Lesson 11 Answer Key

Engage ny eureka math 3rd grade module 4 lesson 11 answer key, eureka math grade 3 module 4 lesson 11 problem set answer key.

Eureka Math Grade 3 Module 4 Lesson 11 Problem Set Answer Key 1

Answer: The area of the rectangle = 48 sq cm.

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 6 x 8 = 48. area of the rectangle = 48 sq cm.

Eureka Math Grade 3 Module 4 Lesson 11 Problem Set Answer Key 2

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 8 x 6 = 48. area = 8 x 6 = (2 x 4) x 6. 2 x ( 4 x 6). 2 x 24. area of the rectangle = 48 sq cm.

Eureka Math Grade 3 Module 4 Lesson 11 Problem Set Answer Key 4

Question 2. Does Problem 1 show all the possible whole number side lengths for a rectangle with an area of 48 square centimeters? How do you know?

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 8 x 6 = 48. area = 8 x 6 = (4 x 2) x 6. area = 4 x 12. area of the rectangle = 48 sq cm.

Question 3. In Problem 1, what happens to the shape of the rectangle as the difference between the side lengths gets smaller?

Answer: The area of the rectangle also decreases= 48 sq cm.

Eureka Math Grade 3 Module 4 Lesson 11 Problem Set Answer Key 6

Answer: The area of the rectangle = 72 sq cm.

Explanation: In the above-given question, given that, area of the rectangle = l x b. where l = length, b = breadth. l = 8 cm and b = 9 cm given. area = l x b. area = 8 x 9. area = 72 sq cm.

b. Julius says a 4 cm by 18 cm rectangle has the same area as the rectangle in Part (a). Place parentheses in the equation to find the related fact and solve. Is Julius correct? Why or why not? 4 Γ— 18 = 4 Γ— 2 Γ— 9 = 4 Γ— 2 Γ— 9 = ___8___ Γ— __9____ = __72____ Area: __72___ sq cm

Answer: Yes, Julius was correct.

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 4 x 18 = 72. area = 4 x 18 = (4 x 2) x 9. area = 8 x 9. area of the rectangle = 72 sq cm.

c. Use the expression 8 Γ— 9 to find different side lengths for a rectangle that has the same area as the rectangle in Part (a). Show your equations using parentheses. Then, estimate to draw the rectangle and label the side lengths.

Eureka-Math-Grade-3-Module-4-Lesson-11-Answer Key-5

Eureka Math Grade 3 Module 4 Lesson 11 Exit Ticket Answer Key

Eureka Math Grade 3 Module 4 Lesson 11 Exit Ticket Answer Key 7

Answer: The area of the rectangle = 64 sq cm.

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 8 x 8 = 64. area = 8 x 8 = (4 x 2) x 8. area = 4 x 16. area of the rectangle = 64 sq cm.

Eureka Math Grade 3 Module 4 Lesson 11 Exit Ticket Answer Key 8

Eureka Math Grade 3 Module 4 Lesson 11 Homework Answer Key

Eureka Math Grade 3 Module 4 Lesson 11 Exit Ticket Answer Key 9

Answer: The area of the rectangle = 36 sq cm.

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 4 x 9 = 36. area = 4 x 9 = (4 x 3) x 3. area = 4 x 9. area of the rectangle = 36 sq cm.

Eureka Math Grade 3 Module 4 Lesson 11 Exit Ticket Answer Key 10

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 1 x 36 = 36. area = 1 x 36 = (1 x 6) x 6. area = 6 x 6. area of the rectangle = 36 sq cm.

Eureka Math Grade 3 Module 4 Lesson 11 Exit Ticket Answer Key 11

Question 2. Does Problem 1 show all the possible whole number side lengths for a rectangle with an area of 36 square centimeters? How do you know?

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 6 x 6 = 36. area = 6 x 6 = (6 x 2) x 3. area = 12 x 3. area of the rectangle = 36 sq cm.

Eureka Math Grade 3 Module 4 Lesson 11 Exit Ticket Answer Key 14

b. Hilda says a 4 cm by 12 cm rectangle has the same area as the rectangle in Part (a). Place parentheses in the equation to find the related fact and solve. Is Hilda correct? Why or why not? 4 Γ— 12 = 4 Γ— 2 Γ— 6 = 4 Γ— 2 Γ— 6 = __8____ Γ— __6____ = ___48___ Area: __48____ sq cm

Explanation: In the above-given question, given that, The area of the rectangle = l x b. where l = length, b = breadth. area = 4 x 12 = 48. area = 4 x 12 = (4 x 2) x 6. area = 8 x 6. area of the rectangle = 48 sq cm.

c. Use the expression 8 Γ— 6 to find different side lengths for a rectangle that has the same area as the rectangle in Part (a). Show your equations using parentheses. Then, estimate to draw the rectangle and label the side lengths.

Eureka-Math-Grade-3-Module-4-Lesson-11-Answer Key-9

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IMAGES

  1. Module 3 Lesson 11 Homework

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  2. Module 3 Lesson 11 Homework Help

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  3. Module 3 lesson 11 homework answers

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  6. Eureka Math Module 3 Lesson 11 Homework

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VIDEO

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  2. Module 3 Lesson 11 Homework Help

  3. Unit 1 Lesson 11 Homework Help

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  5. Revision Unit 11 Homework Correction

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    Eureka Math Grade 3 Module 4 Lesson 11 Problem Set Answer Key. Question 1. The rectangles below have the same area. Move the parentheses to find the unknown side lengths. Then, solve. a. The area of the rectangle = l x b. where l = length, b = breadth. area = 6 x 8 = 48.

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